Among NO_3^{-} (I),AsO_3^{3-} (II),CO_3^{2-} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the geometry,we calculate the hybridization of the central atom using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the

Vedclass · Accepted Answer

$II, IV, V$

Vedclass · Answer

(A) To determine the geometry,we calculate the hybridization of the central atom using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.SpeciesHybridizationGeometry$NO_3^{-}$$sp^2$Trigonal planar (Planar)$AsO_3^{3-}$$sp^3$Pyramidal (Non-planar)$CO_3^{2-}$$sp^2$Trigonal planar (Planar)$ClO_3^{-}$$sp^3$Pyramidal (Non-planar)$SO_3^{2-}$$sp^3$Pyramidal (Non-planar)Thus,the non-planar species are $AsO_3^{3-} (II)$,$ClO_3^{-} (IV)$,and $SO_3^{2-} (V)$.

Among $NO_3^{-} (I)$,$AsO_3^{3-} (II)$,$CO_3^{2-} (III)$,$ClO_3^{-} (IV)$,and $SO_3^{2-} (V)$,the non-planar species are:

Similar Questions

The atomic number of $Sn$ is $50$. The shape of gaseous $SnCl_{2}$ molecule is

The compound $MX_4$ is tetrahedral. The number of $\angle XMX$ angles in the compound is

How many of the following molecules have two lone pairs of electrons on the central atom?
$SF_6$,$BF_3$,$ClF_3$,$PCl_5$,$BrF_5$,$XeF_4$,$H_2O$,$SF_4$

Which among the following molecules is not perfectly flat?

The correct statement about $ICl_5$ and $ICl_4^-$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module